Electric Circuit Theory. Applied Electricity and Electronics by R. Yorke
By R. Yorke
This revised and enlarged variation offers a concise and finished creation to easy strategies established within the fields of electric, digital and keep an eye on engineering and communications. The textual content supplies a lucid therapy of ideas and concept, which, supported by means of 250 labored difficulties and issues of solutions, makes the amount a precious educating relief for the lecturer and an invaluable textual content for self college by way of the coed. This revised and enlarged version features a new bankruptcy on two-port networks, extending the usefulness of the amount in all undergraduate electric and digital engineering classes.
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Additional info for Electric Circuit Theory. Applied Electricity and Electronics
T h e circuit diagram and current waveform are shown in Fig. 2 . 1 . 1) into v(t)=Ri(t) st +L ^ - , st st u ( 0 = RIe + sLIe = I(R + sL) e . 3) is clearly of the form: v(t) = Ve\ where V = I(R + sL). 4). It is shown FIG. 2 . 1 . Circuit and current and voltage waveforms for Problem 2 . 1 . (a) Circuit, (b) Graphs of i(t) and v(i). plotted in Fig. 1(b) for the two possible signs of s. 4) may be rearranged, for comparison with O h m ' s Law of eqn. 5) and so, for exponential waveforms, the impeding effect of resistance and inductance taken together may be combined into a single factor known as the Impedance Function and d e n o t e d by Z ( s ) .
R=250 a 19. For the circuit represented in Fig. L3, calculate (i) the resistance at the terminals AB, given that the numbers on the diagram represent the conductances in Siemens, (ii) the conductance at the terminals AB, given that the numbers represent the resistances in ohms. AO B O FIG. 19). 20. The circuit represented in Fig. 4 is driven by the ramp function v(t) = lit volts, where t is time in seconds. Given that the current i^t) = at + b, evaluate the constants a and b and hence determine the voltage across AB and the currents in the inductive and capacitive branches.
Determine the current needed to discharge the capacitor completely in 20 sec. Sketch the voltage and current waveforms. 16) is used in definite integral form: v(5) = ^i(t)dt+v(0). -. v(5) = 10 f 4 x 1(T dt = 2000 V. Jo 5 3 v(t) = 10 J 4 x 10~ dr = 400r. 6f, 5 W 5 = f i ( 0 df = f 1 . 6 / df = 20 J. Jo h Alternatively, the stored energy can be calculated directly using eqn. 17), W = iCV = i x 1(T x 4 x 1 0 = 20 J. When C is discharging, the voltage is given by eqn. 16). The final voltage is zero.